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KooBits (stylised as KooBits with capitalised K and B) designs and builds digital products for children and educators. KooBits was founded in 2016 by current CEO Stanley, with Professor Sam Ge Shuzhi and Dr Chen Xiangdong. [1] The trio saw an opportunity in the rapid growth of the ebook industry and decided to focus on creating software for ...
The Gifted Education Programme ( GEP) is an academic programme in Singapore, initially designed to identify the top 0.25% (later expanded to 0.5%, then 1%) of students from each academic year with outstanding intelligence. The tests are based on verbal, mathematical and spatial abilities (as determined by two rounds of tests ).
The special case may be described as the problem of giving a partition of a perfect power into few like powers. For k = 4, 5, 7, 8 and n = k or k − 1, there are many known solutions. Some of these are listed below. See OEIS: A347773 for more data. k = 3 3 3 + 4 3 + 5 3 = 6 3 (Plato's number 216) This is the case a = 1, b = 0 of Srinivasa ...
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Stars and bars (combinatorics) In the context of combinatorial mathematics, stars and bars (also called "sticks and stones", [1] "balls and bars", [2] and "dots and dividers" [3]) is a graphical aid for deriving certain combinatorial theorems. It can be used to solve many simple counting problems, such as how many ways there are to put n ...
The Basel problem is a problem in mathematical analysis with relevance to number theory, concerning an infinite sum of inverse squares. It was first posed by Pietro Mengoli in 1650 and solved by Leonhard Euler in 1734, [1] and read on 5 December 1735 in The Saint Petersburg Academy of Sciences . [2]
The Euler–Maclaurin formula provides expressions for the difference between the sum and the integral in terms of the higher derivatives f(k)(x) evaluated at the endpoints of the interval, that is to say x = m and x = n . Explicitly, for p a positive integer and a function f(x) that is p times continuously differentiable on the interval [m,n ...
If N = 1, then there is roughly one recursive subroutine call for every input, but more generally there is one recursive call for (roughly) every N/2 inputs if the recursion stops at exactly n = N. By making N sufficiently large, the overhead of recursion can be made negligible (precisely this technique of a large base case for recursive ...